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What is the area of a triangle having perimeter 32 cm, one side 11 cm and difference of other two sides 5 cm?

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  1. Explanation:

    Sum of other two sides

    (a+b)=31βˆ’11

    =21 and aβˆ’b=5

    β‡’a=21+5\2 13cm

    b=21βˆ’5\2=8cm

    sides of the β–³ = 11,8,13 cm

    S=13+8+11\2=16

    β‡’area=√16(16βˆ’13)(16βˆ’8)(16βˆ’11)

    =√16Γ—3Γ—8Γ—5

    =8√30

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