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Two circles with centre A and B and radius 2 units touch each other externally at β€˜C’, A third circle with centre β€˜C’ and radius β€˜2’ units meets other two at D and E. Then the area of the quadrilateral ABED is

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  1. Explanation:

    Areaβ—»ABED=3Γ—arβ–³ADC

    =3Γ—βˆš3\4(2)^2(ADC is an equilateral triangle)

    =3√3units^2

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