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Three circles of radii 4 cm, 6 cm and 8 cm touch each other pair wise externally. The area of the triangle formed. by the line segments joining-the centres of the three circles is

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  1. Explanation:

    Side β–³ABC=10,14,12

    S=10+14+12\2=18

    area=√s(sβˆ’a).(sβˆ’b)(sβˆ’c)

    =√18Γ—8Γ—4Γ—6=24√6cm^2

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