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Correct Answer: x ≥ y I. 8x2 - 73x + 169 = 0 => 8 x2 - 26x - 52x + 169 = 0 => 2x ( 4x - 13 ) - 13 ( 4x - 13 ) =0 => ( 2x - 13 )(4x - 13 ) = 0 ∴ x = 13/2 or13/4 II. 20y2 - 117y + 169 = 0 => 20y2 - 52y - 65y + 169 = 0 => 4y (5y -Read more
Correct Answer: x ≥ y
I. 8×2 – 73x + 169 = 0
=> 8 x2 – 26x – 52x + 169 = 0
=> 2x ( 4x – 13 ) – 13 ( 4x – 13 ) =0
=> ( 2x – 13 )(4x – 13 ) = 0
∴ x = 13/2 or13/4
II. 20y2 – 117y + 169 = 0
=> 20y2 – 52y – 65y + 169 = 0
=> 4y (5y – 13 ) – 13 ( 5y – 13 ) = 0
=> (4y – 13) (5y – 13) = 0
∴ y = 13/4 or13/5
Clearly, x ≥ y
See lessCorrect Answer: x < y I. 289x√=−25√ Squaring both sides, 289x = 25 => x = 25/289 II. 676y√=10 Squaring both sides, 676y = 100 => y = 100/676 C1early, x < y
Correct Answer: x < y
I. 289x√=−25√
Squaring both sides,
289x = 25
=> x = 25/289
II. 676y√=10
Squaring both sides,
676y = 100
=> y = 100/676
C1early, x < y
See lessCorrect Answer: x > y By equation I × 3 + II × 5, 9x+15y=84 40x−15y=210 => 49x=294 => x = 29449=6 From equation I, 3 × 6 + 5y = 28 => 5y = 28 - 18 = 10 => y = 105 = 2 Clearly, x > y
Correct Answer: x > y
By equation I × 3 + II × 5,
9x+15y=84
40x−15y=210
=> 49x=294
=> x = 29449=6
From equation I,
3 × 6 + 5y = 28
=> 5y = 28 – 18 = 10
=> y = 105 = 2
Clearly, x > y
See lessCorrect Answer: x = y or the relationship cannot be established I. x√−5√/x√=0 => x√×x√5√=0 => x = 5√ II. y3=5(3/2) => y3=(5√)3 => y = 5√
Correct Answer: x = y or the relationship cannot be established
I. x√−5√/x√=0
=> x√×x√5√=0
=> x = 5√
II. y3=5(3/2)
=> y3=(5√)3
=> y = 5√
See lessCorrect Answer: x < y Dividing equation I by II, (y−x)(y+x)/y−x=32/2 => y + x = 16 ...(i) and y - x = 2 ...(ii) Adding both equations, 2y = 18 => y = 9 From equation (i), x = 16 - 9 = 7 Clearly, x < y
Correct Answer: x < y
Dividing equation I by II,
(y−x)(y+x)/y−x=32/2
=> y + x = 16 …(i)
and y – x = 2 …(ii)
Adding both equations,
2y = 18 => y = 9
From equation (i),
x = 16 – 9 = 7
Clearly, x < y
See lessCorrect Answer: x ≤ y I. x2 - 7x + 12 = 0 => x2 - 4x - 3x + 12 = 0 => x ( x - 4 ) - 3 ( x - 4 ) = 0 => ( x - 3 ) ( x - 4 ) = 0 ∴ x = 3 or 4 II. y2 - 9y + 20 = 0 => y2 - 5y - 4y + 20 = 0 => y ( y - 5 ) - 4 ( y - 5 ) = 0 =Read more
Correct Answer: x ≤ y
I. x2 – 7x + 12 = 0
=> x2 – 4x – 3x + 12 = 0
=> x ( x – 4 ) – 3 ( x – 4 ) = 0
=> ( x – 3 ) ( x – 4 ) = 0
∴ x = 3 or 4
II. y2 – 9y + 20 = 0
=> y2 – 5y – 4y + 20 = 0
=> y ( y – 5 ) – 4 ( y – 5 ) = 0
=> ( y – 4 ) ( y – 5 ) = 0
∴ y = 4 or 5
Clearly, x ≤ y
See lessCorrect Answer: x = y or the relationship cannot be established I. x+18√=144√−49√ => x+18√ = ( 12 - 7) = 5 => x + 18 = 25 => x = 25 - 18 = 7 II. y2 = 473 - 409 = 64 => y = 64√=±8
Correct Answer: x = y or the relationship cannot be established
I. x+18√=144√−49√
=> x+18√ = ( 12 – 7) = 5
=> x + 18 = 25
=> x = 25 – 18 = 7
II. y2 = 473 – 409 = 64
=> y = 64√=±8
See lessCorrect Answer: x > y I. 15/x√−2x√=6x√ => 15 - 2 = 6x => 13 = 6x => x = 13/6 II. y√4+7y√/12=1/y√ => 3y√+7y√/12=1/y√ => 10y/√12=1/y√ => 10y = 12 => y = 12/10=6/5
Correct Answer: x > y
I. 15/x√−2x√=6x√
=> 15 – 2 = 6x
=> 13 = 6x
=> x = 13/6
II. y√4+7y√/12=1/y√
=> 3y√+7y√/12=1/y√
=> 10y/√12=1/y√
=> 10y = 12
=> y = 12/10=6/5
See less
Correct Answer: x > y I. 15+9x−−√=11x−−√ => 11x−−√×x−−√ = 24 => 11x = 24 => x = 24/11 II. y√4+5y√/12=1/y√ => 3y√+5y√/12=1/y√ => 3y√+5y√/12=1/y√ => 8y√/12=1/y√=8y√×y√=12 => y = 12/8=3/2 Clearly, x > y
I. 15+9x−−√=11x−−√
=> 11x−−√×x−−√ = 24
=> 11x = 24 => x = 24/11
II. y√4+5y√/12=1/y√
=> 3y√+5y√/12=1/y√
=> 3y√+5y√/12=1/y√
=> 8y√/12=1/y√=8y√×y√=12
=> y = 12/8=3/2
Clearly, x > y
See less