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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x > y I. 15+9x−−√=11x−−√   => 11x−−√×x−−√ = 24   => 11x = 24 => x = 24/11   II. y√4+5y√/12=1/y√   => 3y√+5y√/12=1/y√   => 3y√+5y√/12=1/y√   => 8y√/12=1/y√=8y√×y√=12   => y = 12/8=3/2   Clearly, x > y

    1. Correct Answer: x > y

    I. 15+9x−−√=11x−−√

     

    => 11x−−√×x−−√ = 24

     

    => 11x = 24 => x = 24/11

     

    II. y√4+5y√/12=1/y√

     

    => 3y√+5y√/12=1/y√

     

    => 3y√+5y√/12=1/y√

     

    => 8y√/12=1/y√=8y√×y√=12

     

    => y = 12/8=3/2

     

    Clearly, x > y

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    ‎Correct Answer: x ≥ y   I. 8x2 - 73x + 169 = 0   => 8 x2 - 26x - 52x + 169 = 0   => 2x ( 4x - 13 ) - 13 ( 4x - 13 ) =0   => ( 2x - 13 )(4x - 13 ) = 0   ∴ x = 13/2 or13/4   II. 20y2 - 117y + 169 = 0   => 20y2 - 52y - 65y + 169 = 0   => 4y (5y -Read more

    ‎Correct Answer: x ≥ y

     

    I. 8×2 – 73x + 169 = 0

     

    => 8 x2 – 26x – 52x + 169 = 0

     

    => 2x ( 4x – 13 ) – 13 ( 4x – 13 ) =0

     

    => ( 2x – 13 )(4x – 13 ) = 0

     

    ∴ x = 13/2 or13/4

     

    II. 20y2 – 117y + 169 = 0

     

    => 20y2 – 52y – 65y + 169 = 0

     

    => 4y (5y – 13 ) – 13 ( 5y – 13 ) = 0

     

    => (4y – 13) (5y – 13) = 0

     

    ∴ y = 13/4 or13/5

     

    Clearly, x ≥ y

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x < y   I. 289x√=−25√   Squaring both sides,   289x = 25   => x = 25/289   II. 676y√=10   Squaring both sides,   676y = 100   => y = 100/676   C1early, x < y

    Correct Answer: x < y

     

    I. 289x√=−25√

     

    Squaring both sides,

     

    289x = 25

     

    => x = 25/289

     

    II. 676y√=10

     

    Squaring both sides,

     

    676y = 100

     

    => y = 100/676

     

    C1early, x < y

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x > y   By equation I × 3 + II × 5,   9x+15y=84 40x−15y=210 => 49x=294   => x = 29449=6   From equation I,   3 × 6 + 5y = 28   => 5y = 28 - 18 = 10   => y = 105 = 2   Clearly, x > y

    Correct Answer: x > y

     

    By equation I × 3 + II × 5,

     

    9x+15y=84

    40x−15y=210

    => 49x=294

     

    => x = 29449=6

     

    From equation I,

     

    3 × 6 + 5y = 28

     

    => 5y = 28 – 18 = 10

     

    => y = 105 = 2

     

    Clearly, x > y

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x = y or the relationship cannot be established   I. x√−5√/x√=0   => x√×x√5√=0   => x = 5√   II. y3=5(3/2)   => y3=(5√)3   => y = 5√

    Correct Answer: x = y or the relationship cannot be established

     

    I. x√−5√/x√=0

     

    => x√×x√5√=0

     

    => x = 5√

     

    II. y3=5(3/2)

     

    => y3=(5√)3

     

    => y = 5√

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x < y   Dividing equation I by II,   (y−x)(y+x)/y−x=32/2   => y + x = 16 ...(i)   and y - x = 2 ...(ii)   Adding both equations,   2y = 18 => y = 9   From equation (i),   x = 16 - 9 = 7   Clearly, x < y

    Correct Answer: x < y

     

    Dividing equation I by II,

     

    (y−x)(y+x)/y−x=32/2

     

    => y + x = 16 …(i)

     

    and y – x = 2 …(ii)

     

    Adding both equations,

     

    2y = 18 => y = 9

     

    From equation (i),

     

    x = 16 – 9 = 7

     

    Clearly, x < y

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x ≤ y   I. x2 - 7x + 12 = 0   => x2 - 4x - 3x + 12 = 0   => x ( x - 4 ) - 3 ( x - 4 ) = 0   => ( x - 3 ) ( x - 4 ) = 0   ∴ x = 3 or 4   II. y2 - 9y + 20 = 0   => y2 - 5y - 4y + 20 = 0   => y ( y - 5 ) - 4 ( y - 5 ) = 0   =Read more

    Correct Answer: x ≤ y

     

    I. x2 – 7x + 12 = 0

     

    => x2 – 4x – 3x + 12 = 0

     

    => x ( x – 4 ) – 3 ( x – 4 ) = 0

     

    => ( x – 3 ) ( x – 4 ) = 0

     

    ∴ x = 3 or 4

     

    II. y2 – 9y + 20 = 0

     

    => y2 – 5y – 4y + 20 = 0

     

    => y ( y – 5 ) – 4 ( y – 5 ) = 0

     

    => ( y – 4 ) ( y – 5 ) = 0

     

    ∴ y = 4 or 5

     

    Clearly, x ≤ y

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x = y or the relationship cannot be established   I. x+18√=144√−49√   => x+18√ = ( 12 - 7) = 5   => x + 18 = 25   => x = 25 - 18 = 7   II. y2 = 473 - 409 = 64   => y = 64√=±8

    Correct Answer: x = y or the relationship cannot be established

     

    I. x+18√=144√−49√

     

    => x+18√ = ( 12 – 7) = 5

     

    => x + 18 = 25

     

    => x = 25 – 18 = 7

     

    II. y2 = 473 – 409 = 64

     

    => y = 64√=±8

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x > y   I. 15/x√−2x√=6x√   => 15 - 2 = 6x   => 13 = 6x   => x = 13/6   II. y√4+7y√/12=1/y√   => 3y√+7y√/12=1/y√   => 10y/√12=1/y√   => 10y = 12   => y = 12/10=6/5

    Correct Answer: x > y

     

    I. 15/x√−2x√=6x√

     

    => 15 – 2 = 6x

     

    => 13 = 6x

     

    => x = 13/6

     

    II. y√4+7y√/12=1/y√

     

    => 3y√+7y√/12=1/y√

     

    => 10y/√12=1/y√

     

    => 10y = 12

     

    => y = 12/10=6/5

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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 14, 2022

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  1. Bhanu Chaudhary Professional

    Correct Answer: x < y   I. 19x + 4 = 0   => 19x = -4   => x = −419   II. 21y + 4 = 0   => y = −4/21

    Correct Answer: x < y

     

    I. 19x + 4 = 0

     

    => 19x = -4

     

    => x = −419

     

    II. 21y + 4 = 0

     

    => y = −4/21

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