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Two girls and 4 boys are to be seated in a row in such a way that the girls do not sit together. In how many different ways can it be done?
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Explanation:
4 boys can be seated in a row in 4P4 = 4! ways
Now in the 5 gaps 2 girls can be arranged in 5P2 ways
Hence, the number of ways in which no two girls sit together
= 4!×5P2=4×3×2×5×4
= 480