Bhanu Chaudhary
Poll
Professional
Asked: 2022-03-07T14:35:22+05:30

Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are opéned for one hour each alternatively, the tank will be full in :

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Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are opéned for one hour each alternatively, the tank will be full in :

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    1 Answer

    1. Professional

      Correct Answer: 7 hours
      1/12+1/15+1/20 = 5+4+3/60

      First hour, A and B works together and in second hour A and C works together and It becomes 1 cycle.

      (A+B)’s one hour work

      =5+4=9units

      (A+C)’s one hour work

      =5+3=8units

      They complete (9+8)=17 units in two hours

      17×3=51 units. 2×3= 6 hours

      Remaining Capacity

      =60−51=9units

      Now 3 cycle’s are completes Now pipes(A+B) will start filling then they will fill it in

      =total capacity left/ efficiency of A+B=9/9=1hour

      Total time 6+1=7hours

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