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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 8, 20222022-03-08T19:37:26+05:30 2022-03-08T19:37:26+05:30

Three pipes A, B and C can fill a cistern in 6 hours. After working together for 2 hours, C is closed and A and B fill it in 7 hours more. The time taken by C alone to fill the cistern is

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Three pipes A, B and C can fill a cistern in 6 hours. After working together for 2 hours, C is closed and A and B fill it in 7 hours more. The time taken by C alone to fill the cistern is

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    1 Answer

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    1. Bhanu Chaudhary Professional
      2022-03-08T19:39:18+05:30Added an answer on March 8, 2022 at 7:39 pm

      Correct Answer: 14 hours

       

      let total capacity = 42 units

       

      ∴(A+B+C) per hour work =42/6 =7 units

       

      A+B+Cfills 7 units/hour

       

      They all worked for 2 hour

       

      Total water filled

       

      = 7×2 =14 units

       

      Remaining capacity

       

      = 42−14 = 28

       

      (A+B)’s efficiency=28/7=4units/hr

       

      (A+B) efficiency 4 units/hr.

       

      C’s efficiency =[(A+B+C)−(A+B)] efficiency

       

      = 7−4 = 3 units/h

       

      C can alone fill the cistern in

       

      T.C/efficiency=42/3=14 hrs

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