The odds favouring the event of a person hitting a target are 3 to 5. The odds against the event of another person hitting the target are 3 to 2. If each of them fire once at the target, find the probability that both of them hit the target.

Explanation:

Let A be the event of first person hitting the target,

P(A) =3/3+5=3/8 (odd in favour)

Let B be the event of Second person hitting a target.

P(B)=2/3+2=2/5 (odd against)

Since both events are independent and both will hit the target so,

P(A∩B)= P(A)P(B)=3/8×2/5=3/20