The height of a solid right circular cylinder is 6 metres and three times the sum of the area of its two end faces is twice the area of its curved surface, The radiustqg its base (in metre) is

Explanation:

Height of cylinder h = 6 metres

Let radius of cylinder = r metre

∴ curved surface area =2πrh

Area of end face =πr^2

⇒ Total area of two end faces

⇒2πr^2

Given that3×2πr^2=2×2πrh

3r=2h

r=4cm

∴ Radius of base = 4 cm