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Correct Answer: 6 minutes
A Pipe A is kept open till the tank gets filled.
Let the time for which Pipe A is kept open = t minutes
Therefore, pipe B was kept open for (t – 3) minutes only.
Pipe A fills 1/8th of the tank in a minute and pipe B fills 1/12th of the tank every minute.
Together (A was open for t minutes and B for t-3 minutes) pipe A and pipe B fill ONE full tank
i.e. t/8+t−3/12=1 or 3/t+2/t−6/24 or 5t=30 or 5=6minutes