In a right circular cone, the radius of 1ts base is 7 cm and its height 24 cm. A cross-section is made through the midpoint of the height parallel to the base. The volume of the upper portion is

Explanation:

Volumer of bigger cone

=1\3×π×(7)^2×24

=1\3×22\7×7×7×24

=22×7×8=1232cm\3

volume of smaller cone\volume of bigger cone=h^3\(H)^3

Volume of smaller cone\1232=12^3\24^3

volume of smaller cone =154cm^q3

∴ When the cone is cut in between then the ratio of voulme of smaller cone to the bigger one is always equal to the ratio of the cubes of their heights or radii