If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same in 2 days then the time taken by 15 men and 20 boys to do the same type of work will be

Explanation:

(6m+8b)×10 days

=(26m+48b)×2 days

[m1×t1×d1\w1=m2×t2×d2\w2]

30m+40b=26m+48b

4m = 8b

m = 2b

m\b=2\1

1m (work) = 2 units/day

1b (work) = 1 units/day

Hence,

Total work

=(6×2+8×1)×10

=200 units

Required Time

(15m+20b)

=200\(15×2+20×1)=200\50=4 days