Capacity of tap B is 80% more than that of A. If both the taps are opened simultaneously, they take 45 h to fill the tank. How long will B take to fill the tank alone?

Correct Answer: 70 h

Let time taken by B to fill the tank, a = xh.

Therefore, Time taken by A to fill the tank

b = x+x×80)100=9x/5h

According to the formula,

Time taken by both the taps to fill the tank

t=ab)/a+b

=> 45=x×9x/5/x+9x/5

=> 45×14x/5=9×2/5

Therefore, x = 45×14/9
= 70 h