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Bhanu Chaudhary
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Bhanu ChaudharyProfessional
Asked: March 7, 20222022-03-07T11:23:13+05:30 2022-03-07T11:23:13+05:30

A tank can be filled by two pipes in 20 minutes and 30 minutes respectively when the tank was empty, two pipes were opened. After sometime, the first pipe was stopped and the tank was filled in 18 minutes. After how much time of the start was the first pipe stopped.

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A tank can be filled by two pipes in 20 minutes and 30 minutes respectively when the tank was empty, two pipes were opened. After sometime, the first pipe was stopped and the tank was filled in 18 minutes. After how much time of the start was the first pipe stopped.

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    1. Bhanu Chaudhary Professional
      2022-03-07T13:07:21+05:30Added an answer on March 7, 2022 at 1:07 pm

      Correct Answer: 8 minutes

      Let the first pipe be closed after x min.

      Part filled by two pipes in x minutes = x(1/20+1/30)=5x/60=x/12

      Part filled by the second pipe in (18−x) = 18−x/30

      x/12+18−x/30=1

      10x+72−4x=120

      6x = 120 – 72 = 48

      x = 8 minutes

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