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A mother and a daughter working together can complete a work in 4 days. But if the mother works alone she can complete the work in 6 days. Both of them worked for one day and then the mother had to leave. How long will the daughter take to complete the remaining work?
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Explanation:
According to question, (M + D)’s one day’s work = 1\4
∴ Remaining work = 3\4
M’s one day’s work = 1\6
D’s one day’s work = 1\4−1\6
= 1\12
∴ 1\12th of the work is done by the daughter in 1 day.
=> 3\4th of the work will be done by daughter in 12×3\4 = 9 days.