A man undertakes to do a certain work in 150 days. He employs 200 workers. He discovers that only a quarter of the work is done is 50 days. In order to complete the work on schedule, he must additionally employ

Explanation:

200 persons do 1\4 of the work in 50 days

Therefore, 1 person does 1\4 of work in 50×200 days

1 person does 3\4 of work in 3×50×200 days

n persons do 3\4 of the work in 3×50×200\n

∴3×50×200\n=100

=> n = 300

Already 200 workers are there, hence 100 more persons are to be employed.

M1×D1\W1=M2×D2\W2

200×50\1\4=(200+x)×100\3\4

∴4(200×50)=400(200+x)\3

12(10000)=400(200+x)

300=200+x

Therefore, x = 100

Hence to complete work on time, additional employ required is 100.