A does half as much work as B in three-fourth of the time taken by B. If together they take 18 days to complete the work, how much time shall B take to do it alone?

Explanation:

A:B

time 3:1

eff. 1:2

We have to do time equal so,

Both do the work in 18 days So,

total work = (A+B)′seff.×18

= (4+6)×18 = 180 units.

B will complete the work in

=180\ 6=30 days