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Explanation:
Let (A+B)’s 2 days work
= 2(1\18+1\9) = 2\6 = 1\3
=> Remaining work = 1−1\3 = 2\3
(A + B + C)’s one day’s work
= (1\18+1\9=1\6) = 1\3
1\3 work is completed working all of them together in 1 day.
Hence, 2\3work will be completed in 2 days.
∴Total number of days taken to finish the work is 4 days.