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Explanation:
(B+C)’s one day work = 1\10+1\15=10\60=1\6
(B+C)’s two days work = 1\6×2=2\6=1\3
Remaining work = 1−1\3=2\3
Now 1\12 work can b done by A in one day.
2\3 work can be done by A in 2\3×12 = 8 days