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A and B together can do a piece of work in 30 days, B and C to gether can do it in 20 days, A starts the work and works on it for 5 days, then B takes up and work for 15 days. Finally C finishes the work in 18 days. The number of days in which C alone can do the work where doing it separately is:
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Explanation:
According to the question,
=A+B……..30days
=B+C………….20
=A…….. 5
=B………5+10
=C……….10+8days
= Work done by(A+B)in 5 days
= 2×5=10 units
Work done by(B+C) in 5 days
= 10×3=30 work
Total work (finished till now)……….40 units
=Remaining work =60−40
= 20 units
= Here we find that C does remaining 20 units
in 8 days
C’s efficiency = WorkDay=20 Work\ 8 Days=5\2
C’s efficiency =5\ 2unit/day
Therefore, time taken by C alone to complete the work =60\5×2=24 days