4 men and 10 women were put on a work. They completed 1\3 of the work in 4 days. After this 2 men and 2 women were increased. They completed 2\9 more of the work in 2 days. If the remaining work is to be completed in 3 days, then how many more women must be increased?

Explanation:

Let one man takes x days to complete the work and one woman takes y days to complete the work independently.

Then, 4×4\x + 10×4\y = 1\3

and 6×2\x + 12×2\y = 2\9

Solving above equations, we get

x = 108, y = 216

Let z women be added to complete the work in 3 days.

Then, 6×3\108+3(12+z)\216

= 1−(1\3+2\9) = 4\9

=> 36 + 36 + 3z = 216+4\9 = 96

=> 3z = 96 – 72 = 24 => z = 8