20 men can complete a piece of work in 16 days. After 5 days from the start of the work, some men left. If the remaining work was completed by the remaining men in 18 1\3days, how many men left after 5 days from the start of the work?

Explanation:

Let the number of men who left be x.

Part of work done by 20 men in 5 days = 5\16

∴ Remaining work

= 1−5\16=11\16

According to the question,

M1D1\W1 = M2D2\W2

=> 20×16\1 = (20−x)×55 \ 11\6×3

=> 20×16 = (20−x)×55×16\11×3

=> 20×3=(20−x)×5

=> 60 = 100 -5x

=> 5x = 100 – 60 = 40

=> x= 40\5 = 8