1. Asked: July 24, 2021Category: Quantitative Aptitude - Arithmetic Ability

    The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture ?

    suchetu vothesaru Beginner

    Wine                         Water 8L                              32L 1                :               4 20 %                           80% (original ratio) 30 %                           70% (required ratio)   In  ths case, the percentage of water being reduced when the mixture is being replaRead more

    Wine                         Water

    8L                              32L

    1                :               4

    20 %                           80% (original ratio)

    30 %                           70% (required ratio)

     

    In  ths case, the percentage of water being reduced when the mixture is being replaced with wine.

     

    so the ratio of left quantity to the initial quantity is 7:8

     

    Therefore , 78=[1–K40]

     

    => K = 5 Lit

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