1. ## The diluted wine contains only 8 liters of wine and the rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there was initially 32 liters of water in the mixture ?

Wine                         Water 8L                              32L 1                :               4 20 %                           80% (original ratio) 30 %                           70% (required ratio)   In  ths case, the percentage of water being reduced when the mixture is being replaRead more

Wine                         Water

8L                              32L

1                :               4

20 %                           80% (original ratio)

30 %                           70% (required ratio)

In  ths case, the percentage of water being reduced when the mixture is being replaced with wine.

so the ratio of left quantity to the initial quantity is 7:8

Therefore , 78=[1K40]

=> K = 5 Lit

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