Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. 15x√ + 9/x√ = 11 x√ II. y√/4 + 5y√/12 = 1/y√

### Poll Results

1. Correct Answer: x > y I. 15+9x−−√=11x−−√   => 11x−−√×x−−√ = 24   => 11x = 24 => x = 24/11   II. y√4+5y√/12=1/y√   => 3y√+5y√/12=1/y√   => 3y√+5y√/12=1/y√   => 8y√/12=1/y√=8y√×y√=12   => y = 12/8=3/2   Clearly, x > y

1. Correct Answer: x > y

I. 15+9x−−√=11x−−√

=> 11x−−√×x−−√ = 24

=> 11x = 24 => x = 24/11

II. y√4+5y√/12=1/y√

=> 3y√+5y√/12=1/y√

=> 3y√+5y√/12=1/y√

=> 8y√/12=1/y√=8y√×y√=12

=> y = 12/8=3/2

Clearly, x > y

See less
• 0
• Share
Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. 8×2 – 78x + 169 = 0 II. 20y2 – 117y + 169 = 0

### Poll Results

1. ‎Correct Answer: x ≥ y   I. 8x2 - 73x + 169 = 0   => 8 x2 - 26x - 52x + 169 = 0   => 2x ( 4x - 13 ) - 13 ( 4x - 13 ) =0   => ( 2x - 13 )(4x - 13 ) = 0   ∴ x = 13/2 or13/4   II. 20y2 - 117y + 169 = 0   => 20y2 - 52y - 65y + 169 = 0   => 4y (5y -Read more

I. 8×2 – 73x + 169 = 0

=> 8 x2 – 26x – 52x + 169 = 0

=> 2x ( 4x – 13 ) – 13 ( 4x – 13 ) =0

=> ( 2x – 13 )(4x – 13 ) = 0

∴ x = 13/2 or13/4

II. 20y2 – 117y + 169 = 0

=> 20y2 – 52y – 65y + 169 = 0

=> 4y (5y – 13 ) – 13 ( 5y – 13 ) = 0

=> (4y – 13) (5y – 13) = 0

∴ y = 13/4 or13/5

Clearly, x ≥ y

See less
• 0
• Share
Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. 289x√ + 25√ = 0 II. 676y√ + 10 = 0

### Poll Results

1. Correct Answer: x < y   I. 289x√=−25√   Squaring both sides,   289x = 25   => x = 25/289   II. 676y√=10   Squaring both sides,   676y = 100   => y = 100/676   C1early, x < y

I. 289x√=−25√

Squaring both sides,

289x = 25

=> x = 25/289

II. 676y√=10

Squaring both sides,

676y = 100

=> y = 100/676

C1early, x < y

See less
• 0
• Share
Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. 3x + 5y = 28 II. 8x – 3y = 42

### Poll Results

1. Correct Answer: x > y   By equation I × 3 + II × 5,   9x+15y=84 40x−15y=210 => 49x=294   => x = 29449=6   From equation I,   3 × 6 + 5y = 28   => 5y = 28 - 18 = 10   => y = 105 = 2   Clearly, x > y

By equation I × 3 + II × 5,

9x+15y=84

40x−15y=210

=> 49x=294

=> x = 29449=6

From equation I,

3 × 6 + 5y = 28

=> 5y = 28 – 18 = 10

=> y = 105 = 2

Clearly, x > y

See less
• 0
• Share
Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. x√ – 5√/x√ = 0 II. y3 – 5(3/2) = 0

### Poll Results

1. Correct Answer: x = y or the relationship cannot be established   I. x√−5√/x√=0   => x√×x√5√=0   => x = 5√   II. y3=5(3/2)   => y3=(5√)3   => y = 5√

Correct Answer: x = y or the relationship cannot be established

I. x√−5√/x√=0

=> x√×x√5√=0

=> x = 5√

II. y3=5(3/2)

=> y3=(5√)3

=> y = 5√

See less
• 0
• Share
Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. y2 – x2 = 32 II. y – x = 2

### Poll Results

1. Correct Answer: x < y   Dividing equation I by II,   (y−x)(y+x)/y−x=32/2   => y + x = 16 ...(i)   and y - x = 2 ...(ii)   Adding both equations,   2y = 18 => y = 9   From equation (i),   x = 16 - 9 = 7   Clearly, x < y

Dividing equation I by II,

(y−x)(y+x)/y−x=32/2

=> y + x = 16 …(i)

and y – x = 2 …(ii)

2y = 18 => y = 9

From equation (i),

x = 16 – 9 = 7

Clearly, x < y

See less
• 0
• Share
Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. x2 – 7x + 12 = 0 II. y2 – 9y + 20 = 0

### Poll Results

1. Correct Answer: x ≤ y   I. x2 - 7x + 12 = 0   => x2 - 4x - 3x + 12 = 0   => x ( x - 4 ) - 3 ( x - 4 ) = 0   => ( x - 3 ) ( x - 4 ) = 0   ∴ x = 3 or 4   II. y2 - 9y + 20 = 0   => y2 - 5y - 4y + 20 = 0   => y ( y - 5 ) - 4 ( y - 5 ) = 0   =Read more

I. x2 – 7x + 12 = 0

=> x2 – 4x – 3x + 12 = 0

=> x ( x – 4 ) – 3 ( x – 4 ) = 0

=> ( x – 3 ) ( x – 4 ) = 0

∴ x = 3 or 4

II. y2 – 9y + 20 = 0

=> y2 – 5y – 4y + 20 = 0

=> y ( y – 5 ) – 4 ( y – 5 ) = 0

=> ( y – 4 ) ( y – 5 ) = 0

∴ y = 4 or 5

Clearly, x ≤ y

See less
• 0
• Share
Poll
Professional

## In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer I. x+18√ = 144√ – 49√ II. y2 + 409 = 473

### Poll Results

1. Correct Answer: x = y or the relationship cannot be established   I. x+18√=144√−49√   => x+18√ = ( 12 - 7) = 5   => x + 18 = 25   => x = 25 - 18 = 7   II. y2 = 473 - 409 = 64   => y = 64√=±8

Correct Answer: x = y or the relationship cannot be established

I. x+18√=144√−49√

=> x+18√ = ( 12 – 7) = 5

=> x + 18 = 25

=> x = 25 – 18 = 7

II. y2 = 473 – 409 = 64

=> y = 64√=±8

See less
• 0
• Share
Poll
Professional

## In the fo1lowing question two equations numbered I and II are given. You have to solve both the equations and Give answer I. 15/x√ – 2/x√ = 6x√ II. y√4 + 7y√12 = 1y√

### Poll Results

1. Correct Answer: x > y   I. 15/x√−2x√=6x√   => 15 - 2 = 6x   => 13 = 6x   => x = 13/6   II. y√4+7y√/12=1/y√   => 3y√+7y√/12=1/y√   => 10y/√12=1/y√   => 10y = 12   => y = 12/10=6/5

I. 15/x√−2x√=6x√

=> 15 – 2 = 6x

=> 13 = 6x

=> x = 13/6

II. y√4+7y√/12=1/y√

=> 3y√+7y√/12=1/y√

=> 10y/√12=1/y√

=> 10y = 12

=> y = 12/10=6/5

See less
• 0
• Share
Poll
Professional

## In the fo1lowing question two equations numbered I and II are given. You have to solve both the equations and Give answer I. 361√x+16√ = 0 II. 441√ y + 4 = 0

### Poll Results

1. Correct Answer: x < y   I. 19x + 4 = 0   => 19x = -4   => x = −419   II. 21y + 4 = 0   => y = −4/21

I. 19x + 4 = 0

=> 19x = -4

=> x = −419

II. 21y + 4 = 0

=> y = −4/21

See less
• 0
• Share