A minute hand passes through over 55 minute spaces in an hour i.e. 60 minutes. Let’s find the time taken by the minute hand to cover 60 minute spaces –

55 minute spaces = 60 min

60 minute spaces = X

By cross multiplication, X = (60 x 60)/55 = 60 x 12/11 = 65 5/11 minutes.

As per the data given, the hands of the clock coincide every 64 minutes. This means, there are 64 minute spaces in that clock.

So, in order to get to know how many minutes are lost in that clock in 64 minutes, we need to subtract the minutes in this clock from the minutes in the normal clock ==> 65 5/11 – 64 = 16/11 minutes.

Hence, the given clock is losing 16/11 minutes every 64 minutes. In that clock, 24 hours = 24 x 60 minutes

The watch loses

32 8/11 minutesper dayExplanation:A minute hand passes through over 55 minute spaces in an hour i.e. 60 minutes. Let’s find the time taken by the minute hand to cover 60 minute spaces –

55 minute spaces = 60 min

60 minute spaces = X

By cross multiplication, X = (60 x 60)/55 = 60 x 12/11 = 65 5/11 minutes.

As per the data given, the hands of the clock coincide every 64 minutes. This means, there are 64 minute spaces in that clock.

So, in order to get to know how many minutes are lost in that clock in 64 minutes, we need to subtract the minutes in this clock from the minutes in the normal clock ==> 65 5/11 – 64 = 16/11 minutes.

Hence, the given clock is losing 16/11 minutes every 64 minutes. In that clock, 24 hours = 24 x 60 minutes

64 minutes = 16/11 min lost

24 x 60 minutes = X

X = (16/11)×(1/64)×24×60

X = (1/11) x 360